aadnub1 wrote:
What is the sum of all possible three digit numbers that can be constructed using the digits 3,4,5 if each digit can only be used once in a number?
The explanation:
6 ways to arrange the digits: 345, 354, 453, 435, 543, 534.
Each digit appears twice in the hundreds column, twice in the tens column, and twice in the ones column.
Because each digit appears twice in the hundreds column, you have 3+3+4+4+5+5 = 24 in the hundreds column. ***this is where I lose it. why are we adding the the digits in the first place and why twice?
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