sananoor wrote:
Is x > 0?
1) x < x^2
2) x < x^3
S1 -> x <\(x^2\)
x = -2,\(x^2\) = 4
x = 2,\(x^2\) = 4
Insufficient.
S2 -> x <\(x^3\)
x = 2,\(x^3\) = 8
x = - 1/2,\(x^3\) = - 1/8
Insufficient.
(1+2)
x can be a negative fraction leading to a negative cube less greater than x, or a positive square greater than x.
Insufficient.
E.
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