Here is the OE
Probability is (favorable outcomes)/(total # of possibilities). There are 99 – 20 + 1 = 80 possible values
for c, so the unknown is how many of these c values yield a c3 – c that is divisible by 12.
The prime factorization of 12 is 2 × 2 × 3. There are several ways of thinking about this: numbers are
divisible by 12 if they are divisible by 3 and by 2 twice, or if they are multiples of both 4 and 3, or if half
of the number is an even multiple of 3, etc.
The expression involving
...
Probability is (favorable outcomes)/(total # of possibilities). There are 99 – 20 + 1 = 80 possible values
for c, so the unknown is how many of these c values yield a c3 – c that is divisible by 12.
The prime factorization of 12 is 2 × 2 × 3. There are several ways of thinking about this: numbers are
divisible by 12 if they are divisible by 3 and by 2 twice, or if they are multiples of both 4 and 3, or if half
of the number is an even multiple of 3, etc.
The expression involving
...
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