Bunuel wrote:
pranab223 wrote:
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Bunuel wrote:
Official Solution:
If two different numbers are randomly selected from set\(\{1, 2, 3, 4, 5\}\) , what is the probability that the sum of the two numbers is greater than 4?
A. \(\frac{3}{5}\)
B. \(\frac{7}{10}\)
C. \(\frac{4}{5}\)
D. \(\frac{9}{10}\)
E. \(\frac{19}{20}\)
Let's find the probability of the opposite event and subtract that value from 1. The opposite event would be if we choose 2 different number so that their sum will be
If two different numbers are randomly selected from set\(\{1, 2, 3, 4, 5\}\) , what is the probability that the sum of the two numbers is greater than 4?
A. \(\frac{3}{5}\)
B. \(\frac{7}{10}\)
C. \(\frac{4}{5}\)
D. \(\frac{9}{10}\)
E. \(\frac{19}{20}\)
Let's find the probability of the opposite event and subtract that value from 1. The opposite event would be if we choose 2 different number so that their sum will be
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