Bunuel wrote:
kotharishakti wrote:
Bunuel
It makes sense that the height of the cone will be equal to the radius of the hemisphere.
However, when I tried equating the volumes for both the cone and hemisphere, the solution I am getting is 2 : 1
1\3 x pie x r^2 x h = 1/2 x 4/3 x pie x r^3
h = 2r
Am I missing something here. Please help
It makes sense that the height of the cone will be equal to the radius of the hemisphere.
However, when I tried equating the volumes for both the cone and hemisphere, the solution I am getting is 2 : 1
1\3 x pie x r^2 x h = 1/2 x 4/3 x pie x r^3
h = 2r
Am I missing something here. Please help
Why are you equating volumes? The volume of a cone is obviously less than the volume of the hemisphere it is inscribed in.
I am doing it wrong! Such a silly
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