Bunuel wrote:
3 numbers are randomly selected, with replacement, from the set of integers {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}. If the first number selected is w, the second number selected is x, and the third number is y, what is the probability that w < x < y ?
A. 3/40
B. 28/243
C. 3/25
D. 33/100
E. 64/125
Kudos for a correct solution.
Hi..
the MOST time saving and proper method will be..
1)TOTAL ways 3 can be chosen... 10*10*10
2)Now when will be three W<X<Y when all three are different 10*9*8
But
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