I did this question algebraically - personally I find the above explanations harder to absorb other types of methods. I am going through them though![Image]()
But do let me know if my approach is correct, would be really thankful!
so we have 3x<= 4s + 5, 4s + 5 must add to a multiple of 3*r
So i plugged in values from given to check for incongruities:
A.–20 => putting this in 4s +5, it divides, so 3r is a multiple of 4s + 5
B.–5
...
But do let me know if my approach is correct, would be really thankful!so we have 3x<= 4s + 5, 4s + 5 must add to a multiple of 3*r
So i plugged in values from given to check for incongruities:
A.–20 => putting this in 4s +5, it divides, so 3r is a multiple of 4s + 5
B.–5
...
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