Could you please explain how did you derive the PNc form. I am bit rusty in PNc so I am still not being able to understand how to arrive at this solution. Even-though I
don't need to solve in a DS.
C
1. we cannot create triangles for 5 points of a line but can do that for points that are not collinear. insuff.
2. we don't know the number of points insuff.
1&2 \(C^5_3=\frac{5*4*3*2}{3*2*2}=10\)
...
don't need to solve in a DS.
walker wrote:
C
1. we cannot create triangles for 5 points of a line but can do that for points that are not collinear. insuff.
2. we don't know the number of points insuff.
1&2 \(C^5_3=\frac{5*4*3*2}{3*2*2}=10\)
...
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