Bunuel wrote:
mariachi0204 wrote:
I'm getting SUFFICIENT for statement 2. Here's how:
Given, x+y = 3
X = 3 - y
Substituting for X in the equation;
Y = (3-y)^2 - 6 (3-y) + 9
Y = 9 - 6y + y^2 - 18 + 6y + 9
Cancel out terms,
Y=y^2
Implies y = 1
Therefore x=2
Am I missing something?
Sent from my SM-G900F using GMAT Club Forum mobile app
Given, x+y = 3
X = 3 - y
Substituting for X in the equation;
Y = (3-y)^2 - 6 (3-y) + 9
Y = 9 - 6y + y^2 - 18 + 6y + 9
Cancel out terms,
Y=y^2
Implies y = 1
Therefore x=2
Am I missing something?
Sent from my SM-G900F using GMAT Club Forum mobile app
From y = y^2 it follows that y(y - 1) = 0, so y = 1 or y = 0.
You cannot reduce y = y^2 by y because y can be 0 and we cannot divide by 0. By doing so you loose a root,
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