GMATinsight wrote:
If x is a positive integers and x^3 is divisible by 48 then which of the following is the least number of factors that x may have?
A) 1
B) 3
C) 6
D) 12
E) greater than 12
http://www.GMATinsight.com
x^3 is divisible by 48
i.e.\(x^3 = 2^4 * 3 * a\)
but x^3 must be a perfect cube as well
Perfect Cube: A number with all its prime factors having their powers multiples of 3
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