Assume, the area of the circular region to be 1.
Since the two unshaded portions comprise\(\frac{3}{7}\) and\(\frac{1}{3}\) of the total area,
the shaded portion must contain 1 -(\(\frac{3}{7} + \frac{1}{3})\) of the area.
1 - (\(\frac{3}{7} + \frac{1}{3})\) = 1 - (\(\frac{9+7}{21}\) = 1 -\(\frac{16}{21}\) =\(\frac{5}{21}\) Option D)
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Since the two unshaded portions comprise\(\frac{3}{7}\) and\(\frac{1}{3}\) of the total area,
the shaded portion must contain 1 -(\(\frac{3}{7} + \frac{1}{3})\) of the area.
1 - (\(\frac{3}{7} + \frac{1}{3})\) = 1 - (\(\frac{9+7}{21}\) = 1 -\(\frac{16}{21}\) =\(\frac{5}{21}\) Option D)
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