Data Sufficiency (DS) | Re: The average marks obtained in a test by x students of a class was m.

Average =\(\frac{Sum}{Number}\) =\(\frac{S}{x}\) = m
\(\frac{L}{3}\) = x+3?

1) Lowest 3 marks = L
\(\frac{(S-L)}{(x-3)}\) = x+3
=> S-L = mx+3x-3m-9
=> mx - L = mx+3x-3m-9
=> L = 3m-3x+9
\(\frac{L}{3}\) = m-x+3
m = ?
Insufficient.

2) m = 2x
Doesn't
...

---