Assume a total of 300 people.
Since two-thirds of the people have satellite TV, one-fifth have laptop, and one-tenth have both :
P(Satellite TV) =\(\frac{2}{3}*300 = 200\)
P(Laptop) =\(\frac{1}{5}*300 = 60\)
P(Both) =\(\frac{1}{10}*300 = 30\)
Therefore,
P(Only STV) = P(Satellite TV) - P(Both) = 200 - 30 = 170
P(Only Laptop) = P(Laptop) - P(Both) = 60 - 30 = 30
P(Both) = 30
P(Total) = 300
Fraction of people having, either cable, laptop or both =\( \frac{(170+30+300)}{300} =\frac{23}{30} \)
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Since two-thirds of the people have satellite TV, one-fifth have laptop, and one-tenth have both :
P(Satellite TV) =\(\frac{2}{3}*300 = 200\)
P(Laptop) =\(\frac{1}{5}*300 = 60\)
P(Both) =\(\frac{1}{10}*300 = 30\)
Therefore,
P(Only STV) = P(Satellite TV) - P(Both) = 200 - 30 = 170
P(Only Laptop) = P(Laptop) - P(Both) = 60 - 30 = 30
P(Both) = 30
P(Total) = 300
Fraction of people having, either cable, laptop or both =\( \frac{(170+30+300)}{300} =\frac{23}{30} \)
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