kidderek wrote:
The ratio by weight, measured in pounds, of books to clothes to electronics in Jorge's suitcase initially stands at 8 to 5 to 3. Jorge then removes 4 pounds of clothing from his suitcase, thereby doubling the ratio of books to clothes. Approximately how much do the electronics in the suitcase weigh, to the nearest pound?
A. 3
B. 4
C. 5
D. 6
E. 7
B/C = 8/5
So 5B=8C -----Eqn1
B/C-4 = 16/5
So 5B=16C-64----Eqn2
Solving Eqn 1 & 2
8C=16C-64
So C=8
C/E=5/3
8/E=5/3
E=24/5 = 5
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