Bunuel wrote:
NandishSS wrote:
HiBunuel ,Vyshak ,
If x=2y=4z for positive integers x, y, and z, which of the following can be the average (arithmetic mean) of x, y and 3z?
x=2y ==> y=x/2
x=4z ==> z=x/4
arithmetic mean of x, y and 3z =[x+(x/2)+(3x/4)] /3
=10x/12 ==>5x/6
Can somebody please tell me where am'I going wrong?
If x=2y=4z for positive integers x, y, and z, which of the following can be the average (arithmetic mean) of x, y and 3z?
x=2y ==> y=x/2
x=4z ==> z=x/4
arithmetic mean of x, y and 3z =[x+(x/2)+(3x/4)] /3
=10x/12 ==>5x/6
Can somebody please tell me where am'I going wrong?
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