MathRevolution wrote:
The length of a rectangular photograph is 2 longer than the width of the photograph. If the area of the photograph is 35, what is the width?
A. 3
B. 4
C. 5
D. 6
E. 7
\(w(w + 2) = 35\)
Or,\(w^2 + 2w - 35 = 0\)
Or,\(w^2 + 7w - 5w - 35 = 0\)
Or,\(w(w + 7) -5( w + 7) = 0\)
Or, w = 5 , answer must be (C)
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