Problem Solving (PS) | In the figure shown below AB = AC, angle BAD = 30°, and AE = AD. Then

Ans (D) 15
Let angle ABD = Z, since AB=AC, then angle ACB = Z
In Triangle BAC, angle BAC = 180-2z, hence angle DAE = (180-2z) - 30 = 150-2z --------(1)

Now in smaller triangle ADE, let angle ADE = y, since AD=AE, so angle AED = y
y+y+angle DAE = 180
or 2y
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