redbeanaddict wrote:
Xavier, Yvonne, and Zelda each try independently to solve a problem. If their individual probabilities for success are 1/4, 1/2 and 5/8, respectively, what is the probability that Xavier and Yvonne, but not Zelda, will solve the problem?
A. 11/8
B. 7/8
C. 9/64
D. 5/64
E. 3/64
P(Z solves the problem) = 1 - P(Z doesn't solve the problem)
So, 5/8 = 1 - P(Z doesn't solve the problem)
So, P(Z doesn't solve the problem) =3/8
The question asks us to find P(Xavier and Yvonne solve problem, but Zelda
...
![Midge Ure – A Man of Two Worlds (2026) [Official Digital Download 24bit/96kHz]](http://imghd.xyz/images/2026/05/09/zvc67e2mth34l_600.jpg)
.jpg)
