Bunuel wrote:
If |x - 2| = |x + 3|, x could equal
A. -5
B. -1/2
C. 1/2
D. 5
E. No real solution
With absolute value equations this simple, for me, the method below is easy and fast (less than a minute).
The only way the two sides will be equal is if quantities inside the absolute value brackets are 1) equal or 2) equal but with opposite signs.
So |A| = B or -B*
1. Remove the absolute value bars
2. LHS = RHS or LHS = -RHS
3. Set up the two equations
Case 1: x - 2 = x + 3, OR
Case 2: x - 2 = -(x +
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