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Problem Solving (PS) | Re: If x > y > z, which cannot be the average (arithmetic mean) of x, y an

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chetan2u wrote:

stonecold wrote:
Heychetan2u
There is no doubt in my mind that A is correct option.


But I cannot fathom why E isn't the option too.

Here is what I feel.

For E to be correct =>
x+y+z/3 = y+z/2

Hence y+z=2x

But since y<x and z<x

This can never happen.

Hence E will is correct too.

Hence A and E are both correct.


What am I missing ?


Best
Stone

...

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