Problem Solving (PS) | An empty barrel is filled with oil at a constant rate that takes 10 ho

At what rate is the barrel filled?\(\frac{W}{t}=r\)

\(\frac{(\frac{6}{7})}{10}\) =\(\frac{6}{70}\) = \(\frac{3}{35}\) = r

Work remaining:\(\frac{1}{7}\)

Remaining time to finish,\(\frac{W}{r}=t\) :

(1/7)/(3/35) = \(\frac{1}{7}\) *\(\frac{35}{3}\) =\(\frac{5}{3}\)

= 1\(\frac{2}{3}\) hrs or 1 hr 40 minutes

Answer B
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