Problem Solving (PS) | Re: In the figure above, x = y/2, and z = 3y/8. What is the degree measure

Sum of angles of triangle\(= 180^{\circ}\)

\(x + y + z = 180\)
Given; \(x = \frac{y}{2}\) , and\(z = \frac{3y}{8}\)

\(\frac{y}{2} + y + \frac{3y}{8} = 180\)
\(\frac{4y + 8y + 3y}{8} = 180\)
\(15y = 180 * 8\)
\(y = \frac{180 * 8}{15} => 96\)
\( x =\frac{y}{2} =\frac{96}{2} => 48 \)
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