Bunuel wrote:
The length of side PR of ∆ PQR is 3 times the length of side AC of ∆ ABC. If the length of QS is twice the length of BD, the area of ∆ PQR is how many times the area of ∆ ABC?
(A) 2/3
(B) 3/2
(C) 3
(D) 5
(E) 6
[Reveal] Spoiler:
Let AC = x
Let BD = y
Then
PR = 3x
QS = 2y
Area of ∆ ABC =\(\frac{x*y}{2}\)
Area of ∆ PQR =\(\frac{3x*2y}{2}\) =\(\frac{6xy}{2}\)
Factor out the denominator in both areas.
Area of ∆ PQR/area
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