lbowl wrote:
You should start by translating the problem to symbols:
old= 10r + u (i.e. r=1 u = 3 so 10*1 +3 = 13)
new=r
\(\frac{new}{old} = \frac{1}{14}\) so:
\(\frac{10r + u}{r} = \frac{1}{14}\)
which simplifies to:\(4r = u\)
now we can list posible solutionsstarting:
\(r=1 => u = 4\)
\(r=2 => u = 8\)
\(r=3 => u = 12\) wrong becauseu is unit number so must be smaller or equal to9
hence we have2 solutions
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