cleetus wrote:
Mrs. Robbins started half an hour later than usual for market. But by increasing her speed to 3/2 times her usual speed she reached 10 mins earlier than usual. What is her usual time for this journey?
A. 2 hrs
B. 1 hr
C. 43 MINS
D. 1,5 hrs
We can let Mrs. Robbins’ regular speed = r and her distance = d. Thus, her increased rate is 3r/2. Her regular time is d/r, and so her new time will be d/(3r/2) = 2d/3r. Since she started ½ hour, or 30 minutes, late but arrived at the market 10 minutes
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