Is this a correct approach?
Probability of do not get at least 2 consecutive heads P(A) + probability of get at least 2 consecutive heads P(B) = 1
P(A) = 1 - P(B)
How many times do I get at least 2 consecutive heads ?
HHT (1/8) or THH (1/8) or HHH (1/8)
So P(B) = 3/8
P(A) = 1 - 3/8 = 5/8
Answer C
Probability of do not get at least 2 consecutive heads P(A) + probability of get at least 2 consecutive heads P(B) = 1
P(A) = 1 - P(B)
How many times do I get at least 2 consecutive heads ?
HHT (1/8) or THH (1/8) or HHH (1/8)
So P(B) = 3/8
P(A) = 1 - 3/8 = 5/8
Answer C


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