Bunuel wrote:
\(\frac{{4^8 - 3^8}}{{4^4 + 3^4}}=\)
A. 7
B. 25
C. 156
D. 175
E. 216
Can be solved using the formula :\(a^2 -b^2 = (a+b)(a-b)\)
\(\frac{{4^8 - 3^8}}{{4^4 + 3^4}}\)
\(\frac{(4^4 - 3^4)(4^4+3^4)}{(4^4 + 3^4)}\)
Cancelling\((4^4+3^4\) ); weget;
\((4^4 - 3^4)\)
\((4^2-3^2)(4^2 + 3^2)\)
\((4-3)(4+3)(4^2 + 3^2)\)
\((1)(7)(16 + 9)\)
\((7)(25) = 175\)
Answer (D)...
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