pushpitkc wrote:
Lets name the vertices A,B and C, s.t AC = √5, AB = 1, and BC = 2
Because\(AC^2 = AB^2 + BC^2\) , the triangle is a right angled at B.
Therefore the area =\(\frac{1}{2}\) *Base*Height =\(\frac{1}{2}*2*1 = 2\)(Option E)
...
Lets name the vertices A,B and C, s.t AC = √5, AB = 1, and BC = 2
Because\(AC^2 = AB^2 + BC^2\) , the triangle is a right angled at B.
Therefore the area =\(\frac{1}{2}\) *Base*Height =\(\frac{1}{2}*2*1 = 2\)(Option E)
...
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