2201neha wrote:
Bunuel wrote:
Thanu1083 wrote:
Hi, can you tell me how in example 5 you got the following?
=> \(2 * D_{X} = D_{Y}\) => Distance traveled by Y = twice that of X.
=> Distance traveled by Y = \(\frac{2}{3} *\) half of AB = \(\frac{2}{3} * \frac{5}{2}\) = 5/3
=> \(2 * D_{X} = D_{Y}\) => Distance traveled by Y = twice that of X.
=> Distance traveled by Y = \(\frac{2}{3} *\) half of AB = \(\frac{2}{3} * \frac{5}{2}\) = 5/3
I'd approach this question in a different manner:
X and Y run a race between A and B stations, 5km apart. X starts at 9am from A at speed of 5km/h, reaches B and returns back to A at same speed.Y starts at 9:45am from A at speed 10km/h, reaches B and comes back to A at same speed. At what time do X and
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