Let the Inner triangles unknown angles be x and y,
1. For inner triangle,
x+y+140=180 (sum of all angles in a triangle)
x+y=40 --(1)
2. For triangle PQR,
Sum of all angles = 35+x+y+40+w=180
using (1)
35+40+40+w=180
w=65
1. For inner triangle,
x+y+140=180 (sum of all angles in a triangle)
x+y=40 --(1)
2. For triangle PQR,
Sum of all angles = 35+x+y+40+w=180
using (1)
35+40+40+w=180
w=65



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