Ans is C
let x members on boat Silver Trout and y on Lovely Mary.
A is insufficient as it does not say anything about other boat and so AD ruled out
B is insufficient as same reason above
combine them
0.25x=.50y
x=2y
let straut has 10 member then mary will have 5
clearly this info is sufficient to judge which boat has max numbers of persons.
C is the answer
let x members on boat Silver Trout and y on Lovely Mary.
A is insufficient as it does not say anything about other boat and so AD ruled out
B is insufficient as same reason above
combine them
0.25x=.50y
x=2y
let straut has 10 member then mary will have 5
clearly this info is sufficient to judge which boat has max numbers of persons.
C is the answer
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