Problem Solving (PS) | Re: What will be the remainder when 13^36 is divided by 2196?

We can also use cyclicity of the last digit to answer this question
13ˆ36/2196
The remainder will depend on the last digit of Numerator ie on 3.
Cyclicity of 3 is 4 and the last digits are
3¹=3
3²=9
3³=27
3⁴=81
Now 36/4=9 the digit will have 9 full cycles and the end of the cycle has 1 as the last digit
1³⁶/2196 the reminder will be 1

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