MathRevolution wrote:
If x-7=√x+√7 , x=?
A. 8+2√7 B. 8-2√7 C. 8+√7 D. 8-√7 E. 7+2√8
\(x-7=\sqrt{x}+\sqrt{7} \implies (\sqrt{x}+\sqrt{7})(\sqrt{x}-\sqrt{7}) = \sqrt{x}+\sqrt{7} \implies (\sqrt{x}+\sqrt{7})(\sqrt{x}-\sqrt{7} -1)=0 \)
thus \(\sqrt{x}+\sqrt{7}=0\) or \(\sqrt{x}-\sqrt{7} -1=0\)
thus \(\sqrt{x}=\sqrt{7} +1 \implies x= 8+2\sqrt{7}\)
Answer A









