HeyBunuel ,
can you please check this approach.
Let 7 seats be1 2 3 4 5 6 7
Condition : Children A & B must sit next to each other, and child C must be somewhere to the right of A & B.
So let this be the right side of A & B ---->1 2 3 4 5 6 7 .
Now considering A & B as a single unit, we have 6 seats for them. (Omitting the number 1 seat as if A & B starts sitting from seat number 1, C can't be seated to their right). So we have 6C2 X 2! = 30.
Since 3 out of 7 seats
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can you please check this approach.
Let 7 seats be1 2 3 4 5 6 7
Condition : Children A & B must sit next to each other, and child C must be somewhere to the right of A & B.
So let this be the right side of A & B ---->1 2 3 4 5 6 7 .
Now considering A & B as a single unit, we have 6 seats for them. (Omitting the number 1 seat as if A & B starts sitting from seat number 1, C can't be seated to their right). So we have 6C2 X 2! = 30.
Since 3 out of 7 seats
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