EBITDA wrote:
What is the value of integer n if \((\sqrt{\frac{16}{10^n}})^2=0.04^2\)
A) 0
B) 1
C) 2
D) 3
E) 4
Please explain in detail your answer.
Thank you.
\((\sqrt{\frac{16}{10^n}})^2=0.04^2\)
\({\frac{16}{10^n}}=0.0016\)
\({\frac{16}{10^n}} = 16 * 10^{-4}\)
\({\frac{16}{10^n}} = {\frac{16}{10^4}}\)
\(n = 4\)
Answer E
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