Bunuel wrote:
In the figure above, AD = DC, and BE = EC. The ratio of area of ∆ ABE / area of ∆ BDC is
(A) greater than 0 and less than 1/2
(B) equal to 1/2
(C) greater than 1/2 and less than 1
(D) equal to 1
(E) greater than 1
[Reveal] Spoiler:
Hi..
I. AD=DC
so area of ADB = area of DCB= \(\frac{1}{2}\) area of ABC
BASE is equal and height is same II. BE=EC
so area of AEB = area of AEC=\(\frac{1}{2}\) area of ABC
BASE is equal and height
...
![FLO – Therapy at the Club – Pre-Single [iTunes Plus M4A]](http://is1-ssl.mzstatic.com/image/thumb/Music221/v4/a4/11/88/a41188ed-0f2e-e8d5-1163-d59e373cc58c/26UMGIM30046.rgb.jpg/208x208bb.webp)
.jpg)
