The number k is a three-digit positive integer that has A as its hundreds’ digit, B as its tens’ digit, and C as its units’ digit. If none of the three digits is 0, what is the value of 2k?
(1) A = 3B = 9C : as these are single digit numbers, and a=9c & 3b=9c, so c has to be 1 as any number above that would mean a=9c is not a single digit (i.e. max value can be of 9 only between 0-9) so c=1, a=9 and b=3 so that number k =931 and hence 2k can be calculated and is sufficient.
(2) A/B
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(1) A = 3B = 9C : as these are single digit numbers, and a=9c & 3b=9c, so c has to be 1 as any number above that would mean a=9c is not a single digit (i.e. max value can be of 9 only between 0-9) so c=1, a=9 and b=3 so that number k =931 and hence 2k can be calculated and is sufficient.
(2) A/B
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