DH99 wrote:
Is |a-b| < |a| +|b| ?
Statement 1: \(\frac{a}{b}\)<0
Statement 2: \(a^2b\)<0
Statement 1: implies that either\(a<0\) or\(b<0\)
if\(a<0\) , then\(|a-b| = |-a-b| = |a+b| = |a| +|b|\) . so we get a\(NO\) for the question stem
if\(b<0\) , then\(|a-b| = |a-(-b)| = |a+b| = |a| + |b|\) . so we get a\(NO\) for the question stem
Hence\(Sufficient\)
[b] Statement 2:/b] implies that\(b<0\) but\(a<0\) or\(a>0\)
if both\(a<0\) and\(b<0\) , then\(|a-b| = |-a-(-b)| = |-a+b|<|a| + |b|\) . so we get a\(YES\) for the
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