not too difficult if you understand conceptually and plug in #s.
considerx=10 (easily div by 5).
lets also picky=4 (keep small number to avoid long calculations)
mile 1 = x +(3)*(\(\frac{x}{5}\) ).
- this is b/c the question tells usthe rate is x for the first (\(\frac{1}{4}\)) mile andx/5 for each additional \(\frac{1}{4}\) mi
- Ans: 10c + 3*2c =16c for Mile 1
every additional mile = 4*2c = 8c
4 miles = 16 + 3(8) = 40c total ->KEY: Plug in x=10 & y=4 into A/C to see WHICH GIVE YOU 40
B \( \frac{40+160}{5} \)
...
considerx=10 (easily div by 5).
lets also picky=4 (keep small number to avoid long calculations)
mile 1 = x +(3)*(\(\frac{x}{5}\) ).
- this is b/c the question tells usthe rate is x for the first (\(\frac{1}{4}\)) mile andx/5 for each additional \(\frac{1}{4}\) mi
- Ans: 10c + 3*2c =16c for Mile 1
every additional mile = 4*2c = 8c
4 miles = 16 + 3(8) = 40c total ->KEY: Plug in x=10 & y=4 into A/C to see WHICH GIVE YOU 40
B \( \frac{40+160}{5} \)
...





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