Data Sufficiency (DS) | Re: Cars Y and Z travel side-by-side at the same rate of speed along paral

Posting my way of approach by applying basic trigonometry. Assume the point of meeting to be Q. So distance traveled by Y is PQcosX and distance traveled by Z is PQ. Also assume speeds of Y and Z to be y and z respectively. We know that the time for both should be equal. So, PQcosX/y=PQ/z----cosX/y=1/z----y/z=cosX. Thus we can see that all we need is the value of x.

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