Hi Bunuel,
1 clarification needed..
in statement 2->
we get x=5
y^2 * 121>75 to be proven?
y^2 > or = to zero
even if we take y as 1/2 then y^2 =1/4
1/4 *121=30.25 <75 ---we get answer as NO
Put y=0 then y^2=0
0*121=0 <75 ---we get answer as NO
Put y=-12/11 then y^2=144/121
144/121 *121=144 >75 ---we get answer as YES
if y= integer then definitely y^2 * 121>75
Please let me know what am I lacking in understanding?Acc. to me statement2 is sufficient.
Thanks,
Stuti
1 clarification needed..
in statement 2->
we get x=5
y^2 * 121>75 to be proven?
y^2 > or = to zero
even if we take y as 1/2 then y^2 =1/4
1/4 *121=30.25 <75 ---we get answer as NO
Put y=0 then y^2=0
0*121=0 <75 ---we get answer as NO
Put y=-12/11 then y^2=144/121
144/121 *121=144 >75 ---we get answer as YES
if y= integer then definitely y^2 * 121>75
Please let me know what am I lacking in understanding?Acc. to me statement2 is sufficient.
Thanks,
Stuti


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