Bunuel wrote:
\(\frac{[(n+3)!]^5}{[(n+2)!]^5} =\)
A. 2
B. (n+1)^5
C. (n+2)^5
D. (n+3)^5
E. ((n+3/(n+2))^5
Pick a simple value- 1
a^x/b^x =(a/b)^x
(4!)^5/ (3!)^5 =
4^5
D
\(\frac{[(n+3)!]^5}{[(n+2)!]^5} =\)
A. 2
B. (n+1)^5
C. (n+2)^5
D. (n+3)^5
E. ((n+3/(n+2))^5
Pick a simple value- 1
a^x/b^x =(a/b)^x
(4!)^5/ (3!)^5 =
4^5
D
![FLO – Therapy at the Club – Pre-Single [iTunes Plus M4A]](http://is1-ssl.mzstatic.com/image/thumb/Music221/v4/a4/11/88/a41188ed-0f2e-e8d5-1163-d59e373cc58c/26UMGIM30046.rgb.jpg/208x208bb.webp)
