Bunuel wrote:
The average of four integers is 8. If the greatest of the four integers is 16, what is the minimum possible value of the least of the four integers
A. -32
B. -16
C. -13
D. 0
E. 1
Using the formula average = sum/quantity, we see that the sum of the integers is 8 x 4 = 32. If the greatest integer is 16, the next two “smaller” integers can also be 16. So, the sum of the three largest integers is 16 x 3 = 48 and the smallest-value integer would be 32 - 48 = -16.
Answer: B
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