LakerFan24 wrote:
If the width, depth and length of a rectangle box were each decreased by 50%, by how many percent would the volume of the box decrease?
A) 12.5%
B) 25%
C) 50%
D) 75%
E) 87.5%
We can let L, W, and H be the length, width, and depth of the original rectangular box. Thus, the original volume is L x W x H = LWH, and the new volume is 0.5L x 0.5W x 0.5H = 0.125LWH
The percentage decrease is: (0.125LWH - LWH)/LWH = -0.875 x 100 = -87.5%
Alternate Solution:
Assume that the original dimensions
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