Problem Solving (PS) | If an integer n is divisible by both 6 and 8, then it must

n is divisible by both 6 and 8 means .... n = 6*8

n = 6*8 = (2^4) * 3 implies that the answer must meet two conditions:
(1) be divisible by the product of its prime which is 6=2*3. This by itself narrows down the answer to B=12 or E=18.
(2) contains at most one 3 and at most four 2's. E is not correct because it factors into two 3's which is one too many 3's.

The answer is B.

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