niks18 wrote:
Consider a sequence of seven consecutive integers. The average of the first five integers is \(n\). The average of all the seven integers is:
A. \(n\)
B. \(n+1\)
C. \(k*n\), where \(k\) is a function of \(n\)
D. \(n+\frac{2}{7}\)
E. \(n+2\)
In case of a set of consecutive numbers, Middle number = Average of set
Set of 5 numbers - a, a+1,a+2 , a+3, a+4
Middle number = Average = a+2
but we are given that average for first 5 numbers is = n
hence a+2 = n
Set of 7 numbers - a, a+1, a+2,a+3 , a+4, a+5, a+6
Middle number = Average = a+3
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