Bunuel wrote:
In what ratio should a 20% methyl alcohol solution be mixed with a 50% methyl alcohol solution so that the resultant solution has 40% methyl alcohol in it?
A. 1 : 3
B. 1 : 2
C. 2 : 3
D. 2 : 1
E. 3 : 1
To find the ratio of two solutions in a resultant mixture, weighted average works well. I use this formula:
\((Concen_{A})(Vol_{A}) + (Concen_{B})(Vol_{B} = (Concen_{A+B})(Vol_{A+B})\)
Let A = volume of the solution with 20 percent alcohol
Let B = volume
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