Problem Solving (PS) | Re: Six distinct pair of shoes are in a closet. If three shoes are

I use method 1 - opposite probability

Select 3 shoes with 2 are a pair:

Ways to select a pair: 6C1
Ways to select any shoe from 10 shoes: 10C1
Total ways to choose 3 shoes: 12C3

Probability: (6C1X10C1)/12C3 = 3/11

Probability of no pair of shoes in any three shoes: 1-(3/11)=8/11

Answer
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