Bunuel wrote:
If a – b = 7 and 2ab = 18 then a^2 + b^2 =
A. 67
B. 49
C. 40
D. 31
E. 14
We can square the first equation and we have:
(a – b)^2 = 7^2
a^2 - 2ab + b^2 = 49
Substituting 18 for 2ab, we have:
a^2 - 18 + b^2 = 49
a^2 + b^2 = 67
Answer: A
If a – b = 7 and 2ab = 18 then a^2 + b^2 =
A. 67
B. 49
C. 40
D. 31
E. 14
We can square the first equation and we have:
(a – b)^2 = 7^2
a^2 - 2ab + b^2 = 49
Substituting 18 for 2ab, we have:
a^2 - 18 + b^2 = 49
a^2 + b^2 = 67
Answer: A
![Midge Ure – A Man of Two Worlds (2026) [Official Digital Download 24bit/96kHz]](http://imghd.xyz/images/2026/05/09/zvc67e2mth34l_600.jpg)
.jpg)
