MathRevolution wrote:
[GMAT math practice question]
If 3 persons are selected at random from 8 persons for 3 positions present, vice-present, and secretary, how many such ways are possible?
A. 56
B. 70
C. 240
D. 336
E. 1680
Order matters. President is like first prize, vice-president is like second prize, and secretary is like third prize.
It's a permutation (or use FCP because there are three slots, and 8*7*6 possibilities).
\(_{n}P_{k} = \frac{n!}{(n - k)!}\)
\( _8P_3 = \frac{8*7*6*(5!)}{(5!)}\)
...
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